Amines

Chemistry Chapter 9: Amines

Chapter 9: Amines

Key Topics: Structure and Classification, Preparation Methods (Gabriel Phthalimide & Hofmann Bromamide), Basicity Trends ($pK_b$ values), Distinction Tests (Hinsberg & Carbylamine), and Diazonium Salt Chemistry.

1. Structure & Classification of Amines

Amines can be considered derivatives of ammonia ($\text{NH}_3$) obtained by replacement of one, two, or all three hydrogen atoms by alkyl or aryl groups.

  • Primary ($1^\circ$) Amines: One hydrogen atom of $\text{NH}_3$ is replaced ($\text{R-NH}_2$).
  • Secondary ($2^\circ$) Amines: Two hydrogen atoms are replaced ($\text{R-NH-R'}$).
  • Tertiary ($3^\circ$) Amines: All three hydrogen atoms are replaced ($\text{R-N(R')-R''}$).
  • Structure: Nitrogen is $sp^3$ hybridized with a pyramidal geometry holding an unshared electron pair.

2. Key Methods of Preparation

Reduction of Nitro Compounds: $$\text{R-NO}_2 + 6[\text{H}] \xrightarrow{\text{Sn/HCl or Fe/HCl}} \text{R-NH}_2 + 2\text{H}_2\text{O}$$
Gabriel Phthalimide Synthesis (Exclusive for Pure $1^\circ$ Aliphatic Amines): $$\text{C}_6\text{H}_4(\text{CO})_2\text{N}^-\text{K}^+ + \text{R-X} \rightarrow \text{N-Alkylphthalimide} \xrightarrow{\text{NaOH (aq)}} \text{R-NH}_2 + \text{C}_6\text{H}_4(\text{COO}^-\text{Na}^+)_2$$
Hofmann Bromamide Degradation (Amides to Amines with Loss of 1 Carbon): $$\text{R-CONH}_2 + \text{Br}_2 + 4\text{NaOH} \rightarrow \text{R-NH}_2 + \text{Na}_2\text{CO}_3 + 2\text{NaBr} + 2\text{H}_2\text{O}$$

3. Basicity Comparison & Physical Properties

Phase / Property Aliphatic Amines Aromatic Amines (Aniline)
Aqueous Base Strength ($pK_b$) Stronger bases due to $+I$ inductive effect of alkyl groups. Weaker bases because lone pair is delocalized into the benzene ring via resonance.
Gas Phase Basicity Order $3^\circ > 2^\circ > 1^\circ > \text{NH}_3$ (due to cumulative electron-releasing inductive effect). Significantly lower basicity compared to aliphatic counterparts.
Solubility in Water Lower members are soluble due to hydrogen bonding with water molecules. Sparingly soluble due to the large hydrophobic benzene ring.
Basicity Trend in Aqueous Solution (Aliphatic): $$\text{For methyl series: } (\text{CH}_3)_2\text{NH} > \text{CH}_3\text{NH}_2 > (\text{CH}_3)_3\text{N} > \text{NH}_3$$ $$\text{For ethyl series: } (\text{C}_2\text{H}_5)_2\text{NH} > (\text{C}_2\text{H}_5)_3\text{N} > \text{C}_2\text{H}_5\text{NH}_2 > \text{NH}_3$$

4. Distinction Tests & Chemical Reactions

Carbylamine Test (Specific for Primary Amines - Aliphatic & Aromatic): $$\text{R-NH}_2 + \text{CHCl}_3 + 3\text{KOH (alc.)} \xrightarrow{\Delta} \text{R-NC (Foul-smelling isocyanide)} + 3\text{KCl} + 3\text{H}_2\text{O}$$
Hinsberg Test (Benzenesulphonyl chloride, $\text{C}_6\text{H}_5\text{SO}_2\text{Cl}$):
  • $1^\circ$ Amine: Forms N-alkylbenzenesulphonamide which is soluble in alkali ($\text{KOH}$).
  • $2^\circ$ Amine: Forms N,N-dialkylbenzenesulphonamide which is insoluble in alkali.
  • $3^\circ$ Amine: Does not react with Hinsberg's reagent.
Electrophilic Substitution of Aniline (Acetylation for Monobromination): $$\text{C}_6\text{H}_5\text{NH}_2 + (\text{CH}_3\text{CO})_2\text{O} \xrightarrow{\text{Pyridine}} \text{C}_6\text{H}_5\text{NHCOCH}_3 \xrightarrow{\text{Br}_2 / \text{CH}_3\text{COOH}} \text{p-Bromoacetanilide} \xrightarrow{\text{H}_3\text{O}^+} \text{p-Bromoaniline}$$

5. Diazonium Salts and Their Reactions

Preparation of Diazonium Salts (Diazotisation): $$\text{C}_6\text{H}_5\text{NH}_2 + \text{NaNO}_2 + 2\text{HCl} \xrightarrow{273-278\text{ K}} \text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^- + \text{NaCl} + 2\text{H}_2\text{O}$$
Sandmeyer Reaction (Replacement of $-\text{N}_2^+\text{Cl}^-$): $$\text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^- \xrightarrow{\text{CuCl / HCl}} \text{C}_6\text{H}_5\text{Cl} + \text{N}_2$$ $$\text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^- \xrightarrow{\text{CuBr / HBr}} \text{C}_6\text{H}_5\text{Br} + \text{N}_2$$ $$\text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^- \xrightarrow{\text{CuCN / KCN}} \text{C}_6\text{H}_5\text{CN} + \text{N}_2$$
Azo Coupling Reaction (Synthesis of Dyes): $$\text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^- + \text{C}_6\text{H}_5\text{OH} (\text{Phenol in NaOH}) \xrightarrow{273-278\text{ K}} \text{p-Hydroxyazobenzene (Orange Dye)}$$