Chapter 1 solutions

Chemistry Chapter 1: Solutions

Chapter 1: Solutions

Key Topics: Types of solutions, Methods of expressing concentration, Henry's Law, and Gas Solubility.

1. Definition & Basic Concepts

A solution is defined as a homogeneous mixture of two or more chemically non-reacting substances.

  • Solute: The component present in a smaller proportion in the solution.
  • Solvent: The component present in a larger proportion which determines the physical state of the solution.

2. Types of Solutions

Type of Solution Solute Solvent Common Examples
Solid in SolidSolidSolidCopper dissolved in gold, Alloys (Brass)
Solid in LiquidSolidLiquidGlucose or salt dissolved in water
Solid in GasSolidGasCamphor in nitrogen gas, Smoke
Liquid in SolidLiquidSolidAmalgam of mercury with sodium
Liquid in LiquidLiquidLiquidEthanol dissolved in water
Liquid in GasLiquidGasChloroform mixed with nitrogen gas
Gas in SolidGasSolidSolution of hydrogen in palladium
Gas in LiquidGasLiquidOxygen or $\text{CO}_2$ dissolved in water
Gas in GasGasGasAir (Mixture of $\text{O}_2$ and $\text{N}_2$)

3. Concentration Expressions & Formulae

i. Mass Percentage $(w/W)$: $$\text{Mass\% of solute} = \frac{\text{Mass of solute}}{\text{Total mass of solution}} \times 100$$
ii. Volume Percentage $(v/V)$: $$\text{Volume\% of solute} = \frac{\text{Volume of solute}}{\text{Total volume of solution}} \times 100$$
iii. Mass by Volume Percentage $(w/v)$: $$\text{Mass by Volume\%} = \frac{\text{Mass of solute in grams}}{\text{Volume of solution in mL}} \times 100$$
iv. Parts Per Million (ppm): $$\text{ppm (Component A)} = \frac{\text{Number of parts of component A}}{\text{Total number of parts of all components}} \times 10^6$$
v. Mole Fraction ($\chi$): For a binary mixture of components $A$ and $B$: $$\chi_A = \frac{n_A}{n_A + n_B}$$ $$\chi_B = \frac{n_B}{n_A + n_B}$$ $$\chi_A + \chi_B = 1$$
vi. Molarity ($M$): Moles of solute per liter of solution: $$M = \frac{\text{Moles of solute}}{\text{Volume of solution in Liters}}$$ $$M = \frac{W_B \times 1000}{M_B \times V \text{ (in mL)}}$$
vii. Molality ($m$): Moles of solute per kilogram of solvent: $$m = \frac{\text{Moles of solute}}{\text{Mass of solvent in Kilograms}}$$ $$m = \frac{W_B \times 1000}{M_B \times W_A \text{ (in grams)}}$$
viii. Normality ($N$): Gram equivalents of solute per liter of solution: $$N = \frac{\text{Number of gram equivalents of solute}}{\text{Volume of solution in Liters}}$$ $$N = \frac{W_B \times 1000}{E_B \times V \text{ (in mL)}}$$

4. Henry's Law & Dissolution

Henry's Law states that at a constant temperature, the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas present above the surface of the liquid.

Henry's Law Equation: $$p = K_H \cdot x$$ Where: $$p = \text{Partial pressure of the gas}$$ $$x = \text{Mole fraction of the gas in solution}$$ $$K_H = \text{Henry's Law constant}$$

5. Key Chemical Reactions & Equations

Dissolution of Carbon Dioxide Gas in Water (Aerated Drinks): $$\text{CO}_2\text{(g)} + \text{H}_2\text{O(l)} \rightleftharpoons \text{H}_2\text{CO}_3\text{(aq)}$$
Dissolution of Solid Salts (e.g., Sodium Chloride): $$\text{NaCl(s)} \xrightarrow{\text{H}_2\text{O}} \text{Na}^+\text{(aq)} + \text{Cl}^-\text{(aq)}$$